4=(2x)^2/((0.24-x)*(0.32-3x)^3

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Solution for 4=(2x)^2/((0.24-x)*(0.32-3x)^3 equation: 



4=(2x)^2/((0.24-x)(0.32-3x)^3

We move all terms to the left:

4-((2x)^2/((0.24-x)(0.32-3x)^3)=0



Domain of the equation: ((0.24-x)(0.32-3x)^3)+4!=0

We move all terms containing x to the left, all other terms to the right

((0.24-x)(0.32-3x)^3)!=-4

x∈R



We add all the numbers together, and all the variables

-(2x^2/((-1x+0.24)(-3x+0.32)^3)+4=0

We multiply parentheses ..

-(2x^2/((+3x^2-0.32x-0.72x+0.0768)^3)+4=0

We multiply all the terms by the denominator


-(2x^2=0

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